(x^2-x+2)(x+4)=0

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Solution for (x^2-x+2)(x+4)=0 equation: 


Simplifying
(x2 + -1x + 2)(x + 4) = 0

Reorder the terms:
(2 + -1x + x2)(x + 4) = 0

Reorder the terms:
(2 + -1x + x2)(4 + x) = 0

Multiply (2 + -1x + x2) * (4 + x)
(2(4 + x) + -1x * (4 + x) + x2(4 + x)) = 0
((4 * 2 + x * 2) + -1x * (4 + x) + x2(4 + x)) = 0
((8 + 2x) + -1x * (4 + x) + x2(4 + x)) = 0
(8 + 2x + (4 * -1x + x * -1x) + x2(4 + x)) = 0
(8 + 2x + (-4x + -1x2) + x2(4 + x)) = 0
(8 + 2x + -4x + -1x2 + (4 * x2 + x * x2)) = 0
(8 + 2x + -4x + -1x2 + (4x2 + x3)) = 0

Combine like terms: 2x + -4x = -2x
(8 + -2x + -1x2 + 4x2 + x3) = 0

Combine like terms: -1x2 + 4x2 = 3x2
(8 + -2x + 3x2 + x3) = 0

Solving
8 + -2x + 3x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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